(6x+5)(2x^2-9x-5)=0

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Solution for (6x+5)(2x^2-9x-5)=0 equation:


Simplifying
(6x + 5)(2x2 + -9x + -5) = 0

Reorder the terms:
(5 + 6x)(2x2 + -9x + -5) = 0

Reorder the terms:
(5 + 6x)(-5 + -9x + 2x2) = 0

Multiply (5 + 6x) * (-5 + -9x + 2x2)
(5(-5 + -9x + 2x2) + 6x * (-5 + -9x + 2x2)) = 0
((-5 * 5 + -9x * 5 + 2x2 * 5) + 6x * (-5 + -9x + 2x2)) = 0
((-25 + -45x + 10x2) + 6x * (-5 + -9x + 2x2)) = 0
(-25 + -45x + 10x2 + (-5 * 6x + -9x * 6x + 2x2 * 6x)) = 0
(-25 + -45x + 10x2 + (-30x + -54x2 + 12x3)) = 0

Reorder the terms:
(-25 + -45x + -30x + 10x2 + -54x2 + 12x3) = 0

Combine like terms: -45x + -30x = -75x
(-25 + -75x + 10x2 + -54x2 + 12x3) = 0

Combine like terms: 10x2 + -54x2 = -44x2
(-25 + -75x + -44x2 + 12x3) = 0

Solving
-25 + -75x + -44x2 + 12x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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